Equal volumes of three separate strong acid solutions having , , and are mixed in a single vessel. W — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

Let the volume of each solution be $V$. The $[H^+]$ for the three solutions are $10^{-3} \text{ M}$, $10^{-4} \text{ M}$, and $10^{-5} \text{ M}$. Total moles of $H^+ = (10^{-3} + 10^{-4} + 10^{-5})V = (1 \times 10^{-3} + 0.1 \times 10^{-3} + 0.01 \times 10^{-3})V = 1.11 \times 10^{-3} V$. Total volume is $3V$. Thus, $[H^+] = \frac{1.11 \times 10^{-3} V}{3V} = 3.7 \times 10^{-4} \text{ M}$.