At , pure water has a hydronium ion concentration of . What is the value of the ionic product of wat — Ionic Equilibrium Chemistry Question
Question
At $60^\circ C$, pure water has a hydronium ion concentration of $[H_3O^+] = 10^{-6.7} \text{ mol L}^{-1}$. What is the value of the ionic product of water ($K_w$) at $60^\circ C$?
Answer: C
💡 Solution & Explanation
In pure water, auto-ionization produces equal concentrations of $[H_3O^+]$ and $[OH^-]$. Therefore, $[H_3O^+] = [OH^-] = 10^{-6.7} \text{ M}$. The ionic product of water $K_w = [H_3O^+][OH^-] = (10^{-6.7})^2 = 10^{-13.4}$.
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