What is the total sum of all the atoms present in exactly of the complex hydride synthesized by the — Hydrogen Chemistry Question
Question
What is the total sum of all the atoms present in exactly $1\text{ mole}$ of the complex hydride synthesized by the reaction of diborane ($B_2H_6$) with lithium hydride ($LiH$)?
Answer: 6
💡 Solution & Explanation
The reaction is $2LiH + B_2H_6 \rightarrow 2LiBH_4$. The complex hydride formed is Lithium borohydride ($LiBH_4$). A single molecule of $LiBH_4$ consists of $1$ Li, $1$ B, and $4$ H atoms. The total number of atoms in the formula unit is $1 + 1 + 4 = 6$.
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