When exactly of aluminium chloride () reacts completely with an excess of Lithium hydride (), what i — Hydrogen Chemistry Question
Question
When exactly $1\text{ mole}$ of aluminium chloride ($AlCl_3$) reacts completely with an excess of Lithium hydride ($LiH$), what is the total number of moles of Lithium chloride ($LiCl$) produced as a byproduct in the synthesis of Lithium aluminium hydride?
Answer: 3
💡 Solution & Explanation
The balanced synthesis reaction is $4LiH + AlCl_3 \rightarrow LiAlH_4 + 3LiCl$. According to stoichiometry, $1\text{ mole}$ of $AlCl_3$ yields $3\text{ moles}$ of $LiCl$.
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