In the industrial two-step process of hydroformylation followed by reduction, how many moles of dihy — Hydrogen Chemistry Question

💡 Solution & Explanation

Step 1 (Hydroformylation): $C_2H_4 + CO + H_2 \rightarrow CH_3CH_2CHO$ (consumes $1\text{ mole } H_2$). Step 2 (Reduction): $CH_3CH_2CHO + H_2 \rightarrow CH_3CH_2CH_2OH$ (consumes $1\text{ mole } H_2$). Total dihydrogen consumed = $1 + 1 = 2\text{ moles}$.