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In the catalytic aromatization of exactly one mole of pure n-hexane into benzene using at 773 K, howHydrocarbons Chemistry Question

Question

In the catalytic aromatization of exactly one mole of pure n-hexane into benzene using $Cr_2O_3/Al_2O_3$ at 773 K, how many moles of hydrogen gas ($H_2$) are theoretically evolved as a byproduct?

Answer: 4

💡 Solution & Explanation

The chemical formula for n-hexane is $C_6H_{14}$. The chemical formula for benzene is $C_6H_6$. The aromatization process involves removing hydrogen atoms to create the double bonds of the aromatic ring. The balanced equation is $C_6H_{14} \xrightarrow{773\text{ K}, \text{Cat.}} C_6H_6 + 4H_2$. Therefore, exactly 4 moles of hydrogen gas are evolved.

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