When n-heptane is passed over a catalyst composed of chromium oxide () supported on alumina () at an — Hydrocarbons Chemistry Question

💡 Solution & Explanation

This reaction is called aromatization or catalytic reforming. n-Heptane ($C_7H_{16}$) contains 7 carbon atoms. It undergoes cyclization to a 6-membered ring and subsequent loss of hydrogen ($4H_2$) to form an aromatic ring containing a methyl group, which is toluene (methylbenzene, $C_7H_8$). n-Hexane yields benzene.