Evaluate the alkene 3-ethyl-2-pentene (). How many distinct hyperconjugative canonical structures (n — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

The number of hyperconjugative structures equals the number of $\alpha$ -hydrogens. The double bond carbons are attached to one methyl group (3 $\alpha$ -H) and two ethyl groups (2 $\alpha$ -H each). Total $\alpha$ -hydrogens = 3 + 2 + 2 = 7. Thus, 7 no-bond forms can be drawn.