How many distinct hyperconjugative canonical structures (no-bond resonance forms) can theoretically — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

The number of hyperconjugative structures for a carbocation or free radical is exactly equal to the number of $\alpha$ -hydrogens present. The ethyl carbocation possesses one adjacent $\alpha$ -carbon atom (a methyl group) bearing exactly 3 hydrogen atoms. Thus, 3 no-bond forms can be drawn.