The reaction of chloroform () with a strong base (such as or ) proceeds via an -elimination mechanis — GOC and Organic Chemistry Basics Chemistry Question
Question
The reaction of chloroform ($CHCl_3$) with a strong base (such as $NaOH$ or $KOH$) proceeds via an $\alpha$ -elimination mechanism. What is the highly reactive intermediate generated in this process?
Answer: C
💡 Solution & Explanation
The base abstracts the acidic proton from chloroform to form $CCl_3^-$, which rapidly loses a chloride ion ($Cl^-$) in an $\alpha$ -elimination step to generate the neutral, electron-deficient electrophile, dichlorocarbene ($:CCl_2$).
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