In the balanced redox reaction , what are the respective values of , , and ? — Electrochemistry Chemistry Question

💡 Solution & Explanation

Balancing the redox reaction: Oxidation half is $C_2O_4^{2-} \rightarrow 2CO_2 + 2e^-$. Reduction half is $MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$. Multiplying the oxidation half by 5 and the reduction half by 2 yields: $2MnO_4^- + 5C_2O_4^{2-} + 16H^+ \rightarrow 2Mn^{2+} + 10CO_2 + 8H_2O$. Thus, $x=2$, $y=5$, $z=16$.