Acidified Potassium Permanganate () exhibits immense oxidizing power. When it is treated with an aqu — d and f Block Elements Chemistry Question
Question
Acidified Potassium Permanganate ($KMnO_4 / H^+$) exhibits immense oxidizing power. When it is treated with an aqueous solution containing Iodide ions ($I^-$), what is the specific, final oxidized product containing iodine?
Answer: C
💡 Solution & Explanation
The oxidizing behaviour of $KMnO_4$ is highly dependent on the pH of the medium. In a strictly acidic medium, $KMnO_4$ oxidises Iodide ions ($I^-$) completely to liberate free, molecular Iodine ($I_2$). The reaction is: $10I^- + 2MnO_4^- + 16H^+ \rightarrow 2Mn^{2+} + 8H_2O + 5I_2$. Note that in alkaline or neutral media, it oxidizes $I^-$ to Iodate ($IO_3^-$).
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