During the vital first synthesis step for preparing potassium dichromate, moles of solid chromite or — d and f Block Elements Chemistry Question
Question
During the vital first synthesis step for preparing potassium dichromate, $4$ moles of solid chromite ore ($FeCr_2O_4$) are forcefully roasted with sodium carbonate ($Na_2CO_3$) and atmospheric oxygen ($O_2$). According to the strictly balanced stoichiometric equation for this specific step, exactly how many moles of $CO_2$ gas are liberated?
💡 Solution & Explanation
The balanced chemical equation for the oxidative roasting of chromite ore is: $4FeCr_2O_4 + 8Na_2CO_3 + 7O_2 \rightarrow 8Na_2CrO_4 + 2Fe_2O_3 + 8CO_2$. The stoichiometry rigidly dictates that for every $4$ moles of the $FeCr_2O_4$ reactant consumed, precisely $8$ moles of $CO_2$ are produced and vented.