The atomic radii of elements of the and transition series are nearly identical (e.g., the radius of — d and f Block Elements Chemistry Question
Question
The atomic radii of elements of the $4d$ and $5d$ transition series are nearly identical (e.g., the radius of $Zr \approx Hf$). Which of the following is the primary physical reason for this phenomenon?
💡 Solution & Explanation
In the $5d$ series, the $4f$ orbitals are progressively filled before the $5d$ orbitals. The $f$ -electrons have an extremely poor shielding effect. Thus, the continuous increase in nuclear charge strongly attracts the outermost valence shell, shrinking the atomic radius to virtually offset the expected size increase down the group. This is the lanthanoid contraction, making $Zr$ ($160$ pm) and $Hf$ ($159$ pm) almost identical in size.