Calculate the numerical difference between the Effective Atomic Number (EAN) of Platinum in the comp — Coordination Compounds Chemistry Question
Question
Calculate the numerical difference between the Effective Atomic Number (EAN) of Platinum in the complex $[Pt(NH_3)_6]^{4+}$ and the EAN of Palladium in the complex $[Pd(NH_3)_6]^{4+}$. (Atomic numbers: Pt = 78, Pd = 46)
Answer: 32
💡 Solution & Explanation
Both complexes have a central metal in the $+4$ oxidation state and a coordination number of $6$. EAN of $Pt$ in $[Pt(NH_3)_6]^{4+} = 78 - 4 + 2(6) = 74 + 12 = 86$ (matches Radon). EAN of $Pd$ in $[Pd(NH_3)_6]^{4+} = 46 - 4 + 2(6) = 42 + 12 = 54$ (matches Xenon). The numerical difference is $86 - 54 = 32$.
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