Which of the following complexes of Platinum(IV) will precipitate chloride ions in the form of upon — Coordination Compounds Chemistry Question

💡 Solution & Explanation

Platinum(IV) strongly prefers a secondary valency (coordination number) of 6. (A) $PtCl_4 \cdot 6NH_3 \rightarrow [Pt(NH_3)_6]Cl_4$. Produces 4 ionisable $Cl^-$, so it gives a precipitate. (B) $PtCl_4 \cdot 4NH_3 \rightarrow [Pt(NH_3)_4Cl_2]Cl_2$. Produces 2 ionisable $Cl^-$, so it gives a precipitate. (C) $PtCl_4 \cdot 2NH_3 \rightarrow [Pt(NH_3)_2Cl_4]$. A neutral complex with 0 ionisable $Cl^-$; no precipitate. (D) $PtCl_2 \cdot 2NH_3$ is a Pt(II) complex, $[Pt(NH_3)_2Cl_2]$, which is also neutral and gives no precipitate.