A complex of platinum, ammonia, and chloride produces exactly four ions per molecule in an aqueous s — Coordination Compounds Chemistry Question

💡 Solution & Explanation

The number of ions produced corresponds to the complex ion itself plus the counter ions. (A) $[Pt(NH_3)_4]Cl_4 \rightarrow 5 \text{ ions}$ (If it existed, though Pt(IV) typically has CN=6) (B) $[Pt(NH_3)_2Cl_4] \rightarrow 0 \text{ ions}$ (Neutral complex) (C) $[Pt(NH_3)_5Cl]Cl_3 \rightarrow 1 \text{ complex cation} + 3Cl^- = 4 \text{ ions}$ (D) $[Pt(NH_3)_4Cl_2]Cl_2 \rightarrow 1 \text{ complex cation} + 2Cl^- = 3 \text{ ions}$ Thus, C is the correct structure.