When applying the fundamental Steady State Approximation (SSA) directly to a highly transient chemic — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

Statements A, B, and C collectively define the Steady State Approximation. Because the intermediate is highly reactive (A), it is consumed as fast as it is produced (B), which mathematically justifies setting its net rate of change $\frac{d[I]}{dt}$ to zero (C). Statement D is factually incorrect; if the intermediate formed the product in a slow step, it would bottleneck and accumulate, entirely violating the SSA premises.