Using the data from the previous reaction (Exp 1: , overall order = 2, ), calculate the specific rat — Chemical Kinetics Chemistry Question
Question
Using the data from the previous reaction (Exp 1: $[A] = 0.015 \text{ M}, [B] = 0.15 \text{ M}, \text{Rate} = 1.8 \times 10^{-3} \text{ M min}^{-1}$, overall order = 2, $x=1, y=1$), calculate the specific rate constant $k$ in $\text{L mol}^{-1} \text{ min}^{-1}$.
Answer: 0.8
💡 Solution & Explanation
$\text{Rate} = k[A]^1[B]^1$. Plugging in values from Exp 1: $1.8 \times 10^{-3} = k(0.015)(0.15)$. $k = \frac{1.8 \times 10^{-3}}{0.00225} = \frac{1800 \times 10^{-6}}{2250 \times 10^{-6}} = \frac{180}{225} = 0.8 \text{ L mol}^{-1} \text{ min}^{-1}$.
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