The rate of reaction between two reactants and decreases by a factor of if the concentration of reac — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

Let $\text{Rate} = k[A]^x[B]^y$. When $[B]$ is doubled, new rate is $\text{Rate}_{new} = k[A]^x(2[B])^y = 2^y \times \text{Rate}$. Given that the rate decreases by a factor of 4, $\text{Rate}_{new} = \frac{1}{4} \text{Rate}$. So, $2^y = \frac{1}{4} = 2^{-2}$, resulting in $y = -2$.