Exactly of (molar mass ) is completely dissolved in water to make a solution. What is the numerical — Chemical Equilibrium Chemistry Question
Question
Exactly $0.745\text{ g}$ of $KCl$ (molar mass $= 74.5\text{ g mol}^{-1}$) is completely dissolved in water to make a $1000\text{ mL}$ solution. What is the numerical value of its active mass multiplied by $100$?
Answer: 1
💡 Solution & Explanation
Active mass for an aqueous solution is its molarity. Moles of $KCl = \frac{0.745}{74.5} = 0.01\text{ mol}$. Volume $= 1000\text{ mL} = 1\text{ L}$. Active mass = $\frac{0.01\text{ mol}}{1\text{ L}} = 0.01\text{ mol L}^{-1}$. Multiplying by $100$ gives $0.01 \times 100 = 1$.
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