The experimental dipole moment of is . If the bond angle is , what is the calculated bond moment of — Chemical Bonding Chemistry Question
Question
The experimental dipole moment of $H_2S$ is $0.95\text{ D}$. If the $H-S-H$ bond angle is $96^\circ$, what is the calculated bond moment of a single $S-H$ bond? (Given $\cos(48^\circ) = 0.66$)
Answer: B
💡 Solution & Explanation
The resultant dipole moment $\mu_R$ of two identical bond vectors is given by $\mu_R = 2\mu_{bond}\cos(\theta/2)$. Substituting the values: $0.95 = 2 \times \mu_{S-H} \times \cos(96^\circ/2) = 2 \times \mu_{S-H} \times 0.66$. Solving for $\mu_{S-H}$ gives $0.95 / 1.32 \approx 0.72\text{ D}$.
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