Chemical BondinghardNUMERICAL

The presence of lone pairs distorts ideal bond angles due to increased repulsion. Among the followinChemical Bonding Chemistry Question

Question

The presence of lone pairs distorts ideal bond angles due to increased repulsion. Among the following molecules, how many possess at least one lone pair of electrons localized on the central atom? $NH_3$, $H_2O$, $CH_4$, $PCl_5$, $SF_4$, $ClF_3$, $XeF_4$, $BF_3$.

Answer: 5

💡 Solution & Explanation

The central atoms in $NH_3$ (1 lp), $H_2O$ (2 lp), $SF_4$ (1 lp), $ClF_3$ (2 lp), and $XeF_4$ (2 lp) all retain non-bonding electron pairs. The central atoms in $CH_4$, $PCl_5$, and $BF_3$ use all valence electrons in bonding, possessing 0 lone pairs. Total = 5.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry