Experimental magnetic susceptibility measurements reveal that a particular transition metal complex — Atomic Structure Chemistry Question
Question
Experimental magnetic susceptibility measurements reveal that a particular transition metal complex has a spin-only magnetic moment of roughly $4.90 \text{ BM}$. Based on this value, determine the exact number of unpaired electrons present in the metal ion.
💡 Solution & Explanation
The formula for the spin-only magnetic moment is $\mu = \sqrt{n(n+2)} \text{ BM}$, where $n$ is the number of unpaired electrons. We are given $\sqrt{n(n+2)} \approx 4.90$. Squaring both sides gives $n(n+2) \approx (4.90)^2 \approx 24.01$. The integer solution for $n(n+2) = 24$ is $n = 4$ (since $4 \times 6 = 24$). Thus, there are $4$ unpaired electrons.