The position of both an electron and a helium atom is simultaneously known within a precision of . W — Atomic Structure Chemistry Question

💡 Solution & Explanation

Since $\Delta x$ is identical for both particles, the minimum $\Delta p$ required to satisfy $\Delta x \cdot \Delta p \ge \frac{h}{4\pi}$ will also be identical. However, $\Delta v = \frac{\Delta p}{m}$. Since the electron has a much smaller mass than the helium atom, its uncertainty in velocity ($\Delta v$) will be significantly larger.