According to Heisenberg's Uncertainty Principle, if the uncertainty in the position () of a moving m — Atomic Structure Chemistry Question
Question
According to Heisenberg's Uncertainty Principle, if the uncertainty in the position ($\Delta x$) of a moving macroscopic particle is theoretically observed to be exactly zero, what would happen to the theoretical uncertainty in its momentum ($\Delta p$)?
Answer: C
💡 Solution & Explanation
The relationship is $\Delta x \cdot \Delta p \ge \frac{h}{4\pi}$. Therefore, $\Delta p \ge \frac{h}{4\pi \Delta x}$. As the uncertainty in position $\Delta x$ approaches zero (perfect accuracy), the uncertainty in momentum $\Delta p$ approaches infinity.
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