The angular momentum of an electron revolving in the Bohr orbit of a hydrogen atom is . What will be — Atomic Structure Chemistry Question

💡 Solution & Explanation

According to Bohr's quantization condition, angular momentum $L = \frac{nh}{2\pi}$. It depends only on the principal quantum number $n$, not on the atomic number $Z$. For the $2^{nd}$ Bohr orbit of H, $n=2$. The $1^{st}$ excited state of $Li^{2+}$ also corresponds to $n=2$. Since $n$ is the same, the angular momentum remains exactly $x$.