An electron in a hydrogen-like atom undergoes a transition in such a way that its kinetic energy cha — Atomic Structure Chemistry Question

💡 Solution & Explanation

In any Bohr orbit, the potential energy $PE = -2KE$. Initial state: $PE_1 = -2K$. Final state: $KE_2 = \frac{K}{4}$, so $PE_2 = -2(\frac{K}{4}) = -\frac{K}{2}$. The change in potential energy $\Delta PE = PE_2 - PE_1 = (-\frac{K}{2}) - (-2K) = 2K - \frac{K}{2} = +\frac{3K}{2}$.