Atomic StructurehardNUMERICAL

The ratio of an electron was determined by J.J. Thomson. If the specific charge of an electron is exAtomic Structure Chemistry Question

Question

The $e/m$ ratio of an electron was determined by J.J. Thomson. If the specific charge of an electron is expressed as $x \times 10^{11} \text{ C/kg}$, find the value of $x$ up to two decimal places.

Answer: 1.76

💡 Solution & Explanation

The charge-to-mass ratio ($e/m$) for an electron was determined by Thomson's cathode ray experiment to be $1.758820 \times 10^{11} \text{ C/kg}$. Rounding to two decimal places gives $1.76 \times 10^{11} \text{ C/kg}$, so $x = 1.76$. [1-4]

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