How many moles of glyoxal () are theoretically produced when exactly one mole of benzene undergoes complete, vigorous ozonolysis followed by reductive cleavage with zinc and water?

Question

How many moles of glyoxal ($CHO-CHO$) are theoretically produced when exactly one mole of benzene undergoes complete, vigorous ozonolysis followed by reductive cleavage with zinc and water?

Prashant Kotian · Accepted Answer

Correct answer: 3. Ozonolysis cleaves all carbon-carbon double bonds. Benzene, theoretically represented by three alternating double bonds (Kekule structure), adds three moles of ozone to form a benzene triozonide. Upon reductive cleavage with , the six-carbon ring breaks down into three separate two-carbon fragments, specifically yielding exactly 3 moles of glyoxal.

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