In the preparation of benzene by the reduction of phenol using Zinc dust, what is the difference in — Aromatic Hydrocarbons Chemistry Question
Question
In the preparation of benzene by the reduction of phenol using Zinc dust, what is the difference in molecular weight between the organic reactant (phenol) and the organic product (benzene)? (Atomic weights: C=12, H=1, O=16)
Answer: 16
💡 Solution & Explanation
Phenol has the molecular formula $C_6H_6O$. Its molecular weight is $(12 \times 6) + (1 \times 6) + 16 = 94$. The product, benzene, has the molecular formula $C_6H_6$. Its molecular weight is $(12 \times 6) + (1 \times 6) = 78$. The difference in weight is the single oxygen atom removed by the zinc, which is $16$ g/mol.
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