Aldehydes Ketones and Carboxylic AcidshardNUMERICAL

Oxalic acid is the simplest dicarboxylic acid, with the formula . If exactly 1 mole of pure oxalic aAldehydes Ketones and Carboxylic Acids Chemistry Question

Question

Oxalic acid is the simplest dicarboxylic acid, with the formula $HOOC-COOH$. If exactly 1 mole of pure oxalic acid is reacted completely with an excess of aqueous Sodium Bicarbonate ($NaHCO_3$), how many moles of Carbon dioxide ($CO_2$) gas will be evolved?

Answer: 2

💡 Solution & Explanation

The bicarbonate test relies on the presence of highly acidic $-COOH$ protons. Oxalic acid possesses exactly two such carboxylic acid groups per molecule. Each $-COOH$ group reacts with one $HCO_3^-$ ion to liberate one molecule of $CO_2$. Therefore, 1 mole of oxalic acid will liberate exactly 2 moles of $CO_2$ gas.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry