Consider the synthesis of an ether by reacting sodium isopropoxide with methyl iodide. In the correc — Alcohols Phenols and Ethers Chemistry Question

💡 Solution & Explanation

Sodium isopropoxide ($(CH_3)_2CH-O^- Na^+$) attacks methyl iodide ($CH_3I$) via $S_N2$ to displace iodide, forming isopropyl methyl ether. The structure is $CH_3-CH(OCH_3)-CH_3$. The longest carbon chain is propane (3 carbons). The methoxy group is attached to the central carbon. Therefore, the IUPAC name is 2-methoxypropane, and the locant is 2.