In a Zerewitinoff-type analytical determination, of pure methanol () reacts completely with an excess of methylmagnesium iodide (). Exactly how many moles of methane gas () will be evolved?

Question

In a Zerewitinoff-type analytical determination, $1 	ext{ mole}$ of pure methanol ($CH_3OH$) reacts completely with an excess of methylmagnesium iodide ($CH_3MgI$). Exactly how many moles of methane gas ($CH_4$) will be evolved?

Prashant Kotian · Accepted Answer

Correct answer: 1. Grignard reagents act as exceptionally strong bases in the presence of acidic protons. The slightly acidic proton of the hydroxyl group in methanol immediately reacts with the methyl carbanion equivalent of the Grignard reagent: . One mole of methanol contains one acidic proton, yielding exactly one mole of methane gas.

💡 Solution & Explanation

Practice 22,000+ questions like this