An aqueous solution is prepared by dissolving 0.1 mole in sufficient water to get 100 ml solution at — Ionic Equilibrium Chemistry Question
Question
An aqueous solution is prepared by dissolving 0.1 mole $H_2CO_3$ in sufficient water to get 100 ml solution at 25°C. For $H_2CO_3$, Ka1 = 4.0 * 10^-6 and Ka2 = 5.0 * 10^-11. The only incorrect equilibrium concentration is
Answer: A
💡 Solution & Explanation
C = 1.0 M. [H+] = √(Ka1*C) = √(4*10^-6) = 2.0*10^-3 M (not 6.32*10^-4). Statement (a) is incorrect.
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