At 20°C, two balloons of equal volumes and porosity are filled to a pressure of 2 atm, one with 1 kg and other with 1 kg . The balloon leaks to a pressure of half atm in 1hr. How long will it take for

Question

At 20°C, two balloons of equal volumes and porosity are filled to a pressure of 2 atm, one with 1 kg $N_2$ and other with 1 kg $H_2$. The $N_2$ balloon leaks to a pressure of half atm in 1hr. How long will it take for $H_2$ balloon to reach at pressure of half atm?

Prashant Kotian · Accepted Answer

Correct answer: C. effusion time t ∝ √m. t_h2 / t_n2 = √(m_h2 / m_n2) → t_h2 / 1 hr = √(2 / 28) = √(1/14) = 0.267 hr = 16 min.

💡 Solution & Explanation

Practice 22,000+ questions like this