X and Y are the number of electrons involved, respectively during the oxidation of I – to I2 and S 2 — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Cr2O7 2– + 14H + + 6I –  2Cr 3+ + 3I2 + 7H2O no. of moles e – involved = x = 6 Cr2O7 2– + 3S 2– + 14H +  +S + 2Cr 3+ + 7H2O No. of moles e – involved = y = 6 Sum of x + y = 6 + 6 = 12 ALLEN