One mole of a non-ideal gas undergoes a change of state (2 atm, 3 L, 95 K) - (4 atm, 5 L, 245 K) with a change in internal energy, Δ U = 30.0 L-atm. The change in enthalpy (Δ H) of the process in L-a

Question

One mole of a non-ideal gas undergoes a change of state (2 atm, 3 L, 95 K) -> (4 atm, 5 L, 245 K) with a change in internal energy, Δ U = 30.0 L-atm. The change in enthalpy (Δ H) of the process in L-atm is

Prashant Kotian · Accepted Answer

Correct answer: C. By definition, H = U + PV. Δ H = Δ U + Δ(PV) = Δ U + (P2 V2 - P1 V1). Given Δ U = 30.0 L-atm, P1 V1 = 2 * 3 = 6 L-atm, P2 V2 = 4 * 5 = 20 L-atm. Δ H = 30.0 + (20 - 6) = 44.0 L-atm.

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