See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Conc. of 4 CuSO would not change hence 1 M 1000 2 M 500    . 52. –00208.10 Sol. H H    1 H 119.5 kJ mol    AITS-FT-XV-PCM(Sol.)-JEE(Main)/2021 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9 2 3H   H ?         hyd h actual resonance theo H H H        h actual 3x 119.5 H 150.4      h actual H 358.5 150.4    208.1 