the elevation of boiling point of 0.10 m aqueous CrCl3.xNH3 — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

0.05 m aqueous CaCl2 solution = 0.15 molal solution of non electrolyte Since the elevation in boiling point is double so the molality of given solution of complex = 0.3 m Hence the complex must be producing three ions in the solution, so its formula = [Cr(NH3)5Cl]Cl2 so x = 5