In the following sequence of reactions a compound A, (molecular formula C6H12O2) with a straight cha — JEE Mains Chemistry Past Papers Chemistry Question
Question
In the following sequence of reactions a compound A, (molecular formula C6H12O2) with a straight chain structure gives a C4 carboxylic acid. A is : A O H LiAlH 4 B Oxidation C4 – carboxylic acid vfHkfØ;kvksa ds fuEu Øe esa foo`r Ja`[kyk lajpuk okyk ,d ;kSfxd A, (v.kq lw=k C6H12O2) C4 dkcksZfDlfyd vEy nsrk gSA A gS % A O H LiAlH 4 B vkWDlhdj.k C4 – dkcksZfDlfyd vEy (A) CH3–CH2–CH2–COO–CH2–CH3 (B) OH CH3–CH2–CH–CH2–O–CH=CH2 (C) CH3–CH2–COO–CH2–CH2–CH3 (D) CH3–CH2–CH2–O–CH=CH–CH2–OH
💡 Solution & Explanation
O CH3–CH2–CH2–C–O–CH2–CH3 O H LiAlH 4 CH3–CH2–CH2–CH2–OH + CH3–CH2–OH Oxidation O CH3–CH2–CH2–C–OH + O CH3–C–OH | JEE MAIN-2021 | DATE : 01-09-2021 (SHIFT-2) | PAPER-1 | OFFICAL PAER | CHEMISTRY PAGE # 5