The molar solubility(s) of zirconium phosphate with molecular formula (Zr4+)3, (PO43–)4 is given by relation: (A) 1 sp K (B) 1 sp K (C) 1 sp K (D) 1 sp K

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Question

The molar solubility(s) of zirconium phosphate with molecular formula (Zr4+)3, (PO43–)4 is given by relation:

(A) 1 sp K
(B) 1 sp K
(C) 1 sp K
(D) 1 sp K

Prashant Kotian · Accepted Answer

Correct answer: C. Zr3(PO4)(s) 3Zr+4(aq) + 4PO4–3(aq) 3s 4s Ksp = (3s)3 (4s)4 or s = 1 sp K      

💡 Solution & Explanation