Suppose the inhaled air has partial pressure of water vapour of 5 mm Hg and exhaled air is nearly saturated at body temperature (310 K) with water vapour. The mass of water lost per day by a person as

Question

Suppose the inhaled air has partial pressure of water vapour of 5 mm Hg and exhaled air is nearly saturated at body temperature (310 K) with water vapour. The mass of water lost per day by a person assuming that the normal man breathes 10,000 litre per day. Saturated vapour pressure of water at 310 K is 45 mm Hg.

Prashant Kotian · Accepted Answer

Correct answer: B. δp = 45 - 5 = 40 mm hg = 40/760 atm = 0.0526 atm. v = 10,000 l, t = 310 k. moles of water lost n = δp × v / (rt) = 0.0526 × 10,000 / (0.0821 × 310) = 20.68 mol. mass of water lost = 20.68 × 18 = 372.23 g.

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