Consider two covalent compounds and , if central atom (A) of first compounds has total six electron pairs and central atom (B) of second compound contains total five electron pairs in its valence shel

Question

Consider two covalent compounds $AL_{n_1}$ and $BL_{n_2}$, if central atom (A) of first compounds has total six electron pairs and central atom (B) of second compound contains total five electron pairs in its valence shell and both compounds are planar and non-polar then calculate value of expression $(n_1 - n_2)^2$.

Prashant Kotian · Accepted Answer

Correct answer: 4

**SOLUTION:** $\RIGHTARROW$ NUMBER OF ELECTRON PAIR ON A = 6 $\RIGHTARROW$ NON-POLAR, PLANAR. HENCE $N_1 = 4$
$\RIGHTARROW$ NUMBER OF ELECTRON PAIR ON B = 5 $\RIGHTARROW$ NON-POLAR, PLANAR. HENCE $N_2 = 2$
$(N_1 - N_2)^2 = (4 - 2)^2 = 4$. Step 1: Compare the bond angles: H2O (104.5°), F2O (~103°), Cl2O (~111°), and H2S (~92°). Step 2: In Cl2O, the chlorine atoms are very large and electronegative, causing strong steric and electrostatic repulsions between the two bulky chlorine atoms. Step 3: This severe steric crowding forces the Cl-O-Cl bond angle to open up significantly (~111°), making it the largest among the options. Thus, option (c) is correct.

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