The heat evolved in the combustion of glucose, C6H12O6 is -680 kcal/mol. The mass of produced, when — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

The combustion of 1 mole of glucose produces 6 moles of $CO_2$ and releases 680 kcal of heat: C6H12O6 + 6$O_2$ -> 6$CO_2$ + 6$H_2O$. Moles of $CO_2$ produced when 170 kcal is evolved: n = (6 mol $CO_2$ / 680 kcal) * 170 kcal = 1.5 mol. Mass of $CO_2$ = 1.5 mol * 44 g/mol = 66 g.