See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

See image

Answer: 00000.11

💡 Solution & Explanation

no of equivalent of Al = 0.5 40 60 96500   No of moles of Al = 0.5 40 60 1 96500 3    Mass of Al deposited = 0.5 40 60 27

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry