Consider Al2(OH)6 compound and calculate the value of (X + Y) Z
Where X = Total number of (2c - 2e-) bond.
Y = Total number of (3c - 2e-) bond
Z = Total number of (3c - 4e-) bond

Question

Consider Al2(OH)6 compound and calculate the value of (X + Y) $\div$ Z
Where X = Total number of (2c - 2e-) bond.
Y = Total number of (3c - 2e-) bond
Z = Total number of (3c - 4e-) bond

Prashant Kotian · Accepted Answer

Correct answer: 5 / X = 10, Y = 0, Z = 2.<BR>$\FRAC{10 + 0}{2} = 5$. Step 1: Cyclic (or ring) silicates are formed by sharing two oxygen atoms per tetrahedral SiO4^4- unit. Step 2: The sharing of two oxygen atoms reduces the formula of each unit to SiO3^2-. When these units link in a ring (such as Si3O9^6- or Si6O18^12-), the overall stoichiometry remains (SiO3^2-)_n. Step 3: Therefore, the repeating silicate ion composition that constructs a cyclic skeleton is SiO3^2-, matching option (c).

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