See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

when n is odd E is divisible by19 when n is odd                      (III) 10 20 10 18 16 16 0 10 1 10 2 10 C C C C C C .........                        20 18 16 10 10 20 10 0 1 2 10 9 8 2 2 2 10 10 10 10 0 1 2 10 2 10 10 10 2 10 Coefficient of x in C 1 x C 1 x C 1 x ....... Coefficient of x in C 1 x C 1 x C 1 x ........ Coefficient of x in 1 x 1 Coefficientof x in 2x x 2                                         (IV) 14 r 1; 14 r 14 r 1 r r 1 r 1 r r 2 r 1 T Cr x T C x ;T C x          14 14 14 r r 1 r 1 By the given condition, 2 C C C     AITS-FT-VIII (Paper-2)-PCM(Sol.)-JEE(Advanced)/20 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 18   14 14 r 1 r 1 14 14 r r C C 2 C C 14 r 1 1 r 2 14 r 1 r 1 r 14 r 2 15 r r 1 r 9                      SECTION – C