At what temperature will the total translational kinetic energy of 0.30 mole of He gas be the same a — States of Matter and Gaseous State Chemistry Question
Question
At what temperature will the total translational kinetic energy of 0.30 mole of He gas be the same as the total translational kinetic energy of 0.40 mol of Ar at 400 K?
Answer: A
💡 Solution & Explanation
Total translational KE = 3/2 * n * R * T. For equal kinetic energy: n1 * T1 = n2 * T2 => 0.30 * T1 = 0.40 * 400 => T1 = 160 / 0.3 = 533.3 K .
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