500 mL of 1.2 M KI | JEE Mains Chemistry Past Papers — Chem-Mantra

JEE Mains Chemistry Past PapershardNUMERICAL

Question

500 mL of 1.2 M KI

Answer: .

💡 Solution & Explanation

MnO4 – + I –  MnO2 + I2 I2 + S2O3 2–  S4O6 2– + I – gram eq of KMnO4 = gram eq of Na2S2O3 0.2 0.1 V 1      V = 3 L

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